i dont get this at all im really counfused can someone help?
1. CSC^2X + COT^2X (in terms of cos)
2. cotx (sinx-cscx) (any terms)
3. 1 + tan^2x / cscxsecx (any terms)
btw the ^2 is the power...if anyone can help...thanks!
2006-10-03 11:10:51 · 4 answers · asked by devincr 1 in Education & Reference ➔ Homework Help
Look through these
http://en.wikipedia.org/wiki/Trigonometric_identity
and see if any of them can be used to simiplify your equations.
2006-10-03 11:20:00 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
use angle identities
I don't really remember what the identities were
I remembered that 1 + tan^2x is sec^2x I think...or it's cot^2x
cotx(sinx-cscx) distribute the cotx with the sinx-cscx so you're left with cosx-(cos^2x / sin^2x)
I'm was only 14 when I learned all this...sad for you
2006-10-03 18:24:50 · answer #2 · answered by Li 2 · 0⤊ 0⤋
well i know that csc= 1/sin^2x and cot= 1/tan^2x, if that helps at all. sorry, that's all can remember.
I can also simplify #2 down to cotx (sin^2x-1)
2006-10-03 18:20:02 · answer #3 · answered by Kristin 2 · 0⤊ 0⤋
Use the Trig identities and start substituting
http://en.wikipedia.org/wiki/List_of_trigonometric_identities
2006-10-03 18:24:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋