we got this question in physics and i was wondering if you could explain to me how to do it. i started(work below) but not sure if i'm doing it right.
A 438kg car is accelerating at 2.55 m/s^2. if the coefficient of friction felt by the car is .0500, what is the total force acting east on the car? (hint: 4 calculations needed)
1st i did F=ma
438kg*2.55m/s^2 and got 1120 N
then i did Fsubf=uFsubn
.0500*1120N=56N
then i did 1120N -56 N=1064N
i thought this was the net force. but it says i need 4 calculations and i only have 4.
Could you explain what i'm doing wrong?
Thank you so much
2006-10-03
11:06:42
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2 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics