what volume of acid is needed to neutralize 1mL of saturated bicarbonate solution?

Answer 1

The solubility of different bicarbonates is slightly different. Using Sodium bicarbonate at 20 degrees C), a saturated solution in water would contain about 100.1 g/L

The neutralization reaction might look like:

NaHCO3 + HCl → NaCl + H2O + CO2 or

(HCO3)-1 + H+ → H2O + CO2

One (1.00) mL of saturated bicarbonate would contain:

100.1 g/L / 1000 mL/L = 0.1001 grams

the number of moles would be:

0.1001 g / 80.007 g/mole = 0.00125 moles

You need the concentration of the acid in moles/L

for 0.100 M acid

0.00125 moles / 0.100 moles/L = 0.0125 L = 12.5 mL