The circumference of a sphere is two pi times the radius. (The Earth is actually an oblate spheroid, but the math works out the same as for a sphere.) Thus, if you increase the circumference by one meter, the radius must increase by one meter divided by two pi, or 159 millimeters.
Even though 159 millimeters doesn't seem like much, it would take about 447,000,000,000,000 metric tons of rock to increase the Earth's radius by 159 millimeters.
2006-10-03 10:35:24
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answer #1
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answered by Deep Thought 5
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If we assume that the circumference of the earth at the equator is 24,901.55 miles (40,075.16 kilometers).
That is 40,075,160 meters then the radius will be 6,378,159.809m
If we add a meter .....
That is 40,075,161 meters then the radius will be 6,378,159.968m
0.159 meters, about 16 cm
I think....
2006-10-03 17:44:59
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answer #2
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answered by Nick C 2
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C=2Pi*R
dC/dR=2Pi
for one meter
dC=1
1/dR=2Pi
dR=1/2Pi
dR=0.159meters
The cute bit about this is it is independant of the size now. I mean if you did this for jupiter, a tennis ball, the sun the change would be the same.
2006-10-03 17:44:02
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answer #3
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answered by slatibartfast 3
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C = 2*Pi*r
C + 1 = (2*Pi*r) + 1
r = [(C + 1)/(2*Pi)] - (1 / 2*Pi)
Now just find the circumference of the sun, and plug it into this equation.
2006-10-03 17:36:20
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answer #4
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answered by عبد الله (ドラゴン) 5
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p:2=24
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hehehe gibberish i forgot algebra and have to many problems in my head to answer but thanx for the 2 points im about to be 25 so i just got out of school lol
2006-10-03 17:39:53
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answer #5
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answered by Anonymous
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r=c/2pi
new-r=(c+1)/2pi
so
new-r - r =
1/2pi [c+1-c]
= 1/(2pi) meters
2006-10-03 17:35:55
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answer #6
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answered by k_e_p_l_e_r 3
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why would you do it
2006-10-03 17:32:07
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answer #7
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answered by Anonymous
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