1. do these ( ) <--called parenthesis
2. then these [ ] <---- called brackets
3. then these { } <---- called braces
2006-10-03 10:52:02
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answer #1
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answered by Katie 5
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You have in this example parentheses (), braces { }, and brackets [ ].
{7[4+3(3x+2)]2-(-9)}
First look at the parentheses. It shows that (3x+2) is multiplied
by the number three. So do the multiplication and get 9x+6. So we can now replace 3(3x+2) by its equal 9x+6.
Now our expression looks like this:
{7[4+9x + 6]2- (-9)}
Now look inside the brackets. You can replace 4+9x+6 by 9x+10
Now our expression looks like this:
{7[9x+10]2 - (-9)} The 9x+10 is being multiplied by both 7 and 2 so we get 14[9x+10] = 126x+140 and our expression becomes:
{126x +140 - (-9)}. Since minus times minus = plus we can replace -(-9) with just +9 so we get:
{126x +140 +9} = {126x + 149} =126x +149
Hope this helped
2006-10-03 10:49:24
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answer #2
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answered by ironduke8159 7
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The different types of parentheses are used to distinguish themselves from one another, for easier reading. It's better than
(7(4+3(3x+2))2-(-9))
because you don't have to figure out with ( goes with which ). But otherwise, they all serve the same purpose.
2006-10-03 10:21:41
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answer #3
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answered by James L 5
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Do you have the value of x?
If you do do the () first the [] second and the {} last and 2-(-9) is equal to 18
2006-10-03 10:28:33
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answer #4
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answered by Anonymous
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{7[4+3(3x+2)]2-(-9)}
{7[4+9x+18]2-(-9)}
{7[9x+22]2-(-9)}
{7.2[9x+22]-(-9)}
{14[9x+22]-(-9)}
{14[9x+22]-(-9)}
{[126x + 308 ] -(-9)}
{[126x + 308 ] + 9}
{126x + 308 +9}
{ 126x +317 }
2006-10-03 10:24:40
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answer #5
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answered by king2006 2
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They probably all mean the same, they just look different to make it easier to see what matches what.
2006-10-03 10:21:03
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answer #6
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answered by Anonymous
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the answer is 294x + 205
2006-10-03 10:22:19
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answer #7
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answered by jinenglish68 5
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FOIL
Do the arithmetic in this order of the terms:
First
Outer
Inner
Last
2006-10-03 10:21:29
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answer #8
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answered by Jay 6
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you have to work from the inside out
2006-10-03 10:22:11
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answer #9
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answered by Anonymous
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