2006-10-03 09:55:38 · 22 answers · asked by Danny D 1 in Education & Reference ➔ Homework Help
27
2, 7, 12, 17, 22, 27
you add 10 every other number.
2006-10-03 09:57:31 · answer #1 · answered by stevelydon11 1 · 0⤊ 0⤋
2+5=7, 7+5=12, 12+5=17, 17+5=22
2006-10-03 16:57:35 · answer #2 · answered by Birdbrain 4 · 0⤊ 0⤋
The series can be represented by 2+5n, so for the 6th term, you just substitute 5 (6th number from 0) where there is an "n" and you get:
2+5*5=2+25=27
2006-10-03 17:00:35 · answer #3 · answered by paisak79 3 · 0⤊ 0⤋
2, 7, 12, 17, 22, 27
6th term is 27
2+5=7+5=12+5=17+5=22+5=27
2006-10-03 20:11:46 · answer #4 · answered by mubryan10 2 · 0⤊ 0⤋
Well, the pattern here is that you add 5 to each number.
2+5=7
7+5=12
12+5=17
17+5=22
22+5=27
so, 2 is the first term, 7 the second and so forth, til you get 27 is the sixth term.
2006-10-03 16:57:44 · answer #5 · answered by jimboradley 2 · 0⤊ 0⤋
27
2006-10-03 16:57:50 · answer #6 · answered by sandbag22 1 · 0⤊ 0⤋
5th term is 22
6th term is 27
Just add 5
Also if you look at each alternate number the prefix number will be an increment of 1 whereas the second number will remain the same
2, 12, 22, 32, 42
also
7, 17, 27, 37
and so on.
I think thats your answer mate.
2006-10-03 17:02:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
27
you add 5 after each number.
2, 7, 12, 17, 22, 27...
2006-10-03 16:57:45 · answer #8 · answered by Lanie 3 · 0⤊ 0⤋
I have no idea what is meant by 6th term....but I imagine they just want to know the 6th number in the sequence which is obviously 27, five being 22....
2006-10-03 16:58:08 · answer #9 · answered by WitchTwo 6 · 0⤊ 0⤋
The sixth term is 27
I did this by breaking the pattern down and coming up with the equation...
43[(n-1)^2]
___________
(62n - 53)
Then by applying that to the the situational interval formula
and then tieing that into
43X x 32y/57u (87388u+ 7883) = 54
then you simply divide that by 2
54/2 =27 and you get 27!
2006-10-03 17:02:10 · answer #10 · answered by Anonymous · 0⤊ 0⤋