I need help with math home work HELP! IT is easy just I don't get it?

Question

Here is the question and the problem: Write the prime factorization of each number. Then write it using exponents
36=____________________________=_____________
Please help first one to help me get a problem right hets best answer the question goes for all of them that are on this answer question 40=________________=__________
90=_________________=________
PLEASE HELP

I aslo need help with what is the primefactorization of 50

Answer 1

prime factors are just numbers that can no longer be divided into evenly by any other number except 1 and itself, for example the number 3... what divides into 3 that isnt 1 or 3? nothing, its prime.

so, looking for the prime factor of 36, all you have to do is figure out what divdes into it easily. factor trees work pretty well for me, write the number 36 down, then put two arrows pointing down to the numbers that factor into 36, which, going the easy way would be 2 and 18. since we know 2 is prime then we can circle it and move onto 18. now we need to reduce 18, two simple factors of 18 would be 3 and 6, 3 is prime so go ahead and circle that one, 6 however is not. now do the same for 6, since 2x3=6 then put down 2 and 3 as your factors. again, 2 and 3 are prime, circle those. so what've we got? we've got two 2's and two 3's, so 2x2x3x3 right? now we need to make it shorter using exponents, so 2x2=2 to the second power (that little 2 at the top of the number 2, I dont know how to type it, hehe sorry) and 3 to the second power (again with the little 2 at the top since you have two 3's)


Sorry its so long, hehe I hope it helped, if it doesnt just post again and we'll see what we can do

Answer 2

Numbers multiplied together are called factors. So, 36=3 X 12, the 3 and 12 are factors of 36 and 36=3 X 3 X 4. the factors are the 3s and the 4 or 36=3 X 3 X 2 X 2 which is called the prime factorization.
Here are steps to follow to find prime factorization.
1. check to see if 2 is a factor of the number.
if so, write the number as a product of 2 and another factor.
2. if 2 is not a factor, then continue to check each prime number, 3, 5, 7, 11,..., until you can write the product as two factors.(prime numbers are numbers that can onlly be divided by 1 or themselves.)
3. Take the second factor from either step 1 or step 2. and repeat steps 1 and 2.
4. Continue until you can no longer factor.
5. Write the original number as a product of prime factors.
For example, to find the prime factorization of the number 30.
1.check to see if 2 is a factor of 30. Since it is write 30 as the product....30=2 X 15
2.check to see if 2 is a factor of 15. It is not.
3.check to see if 3 is a factor of 15. Since it is write 15 as the product.....15=3 X 5
4. 3 and 5 have no more factors.
5.write 30 as a product of prime numbers....30=2 X 3 X 5
Now to write 36 as an exponent. What multiplied by itself =36?
6 X 6=36, 36=2 X 2 X 3 X 3, or 36=2 to the power of 2, multiply by 3 to the power of 2.
Factor the 40, 40=2 X 20, 40=2 X 2 X 10. 40=2 X 2 X 2 X 5 (prime factorization)
40=2 to the power of 3 multiplied by 5.
90=2 X 45, 90=2 X 3 X 15, 90=2 X 3 X 3 X 5 (prime factorization)
90=10 multiplied by 3 to the power of 2.
I'm pretty sure that is correct.

Answer 3

Here we go. Remember, a prime number has only factors of 1 and itself. For instance, 5 is a prime number since you can only divide evenly by 5 and by 1.

36: 4 x 9 = 2 x 2 x 3 x 3. Exponents: 2^2 x 3^2 (Two squared times three squared)

40: 4 x 10 = 2 x 2 x 5 Exponents: 2^2 x 5

90: 9 x 10 = 3 x 3 x 2 x 5. Exponents: 3^2 x 2 x 5

Regards,

Mysstere

Answer 4

The number of not necessarily distinct prime factors of a number is denoted (Hardy and Wright 1979, p. 354) or . For example, has a single distinct prime factor (so ), but two total prime factors, so . The number of prime factors is

(2)

The first few values for , 2, ... are 0, 1, 1, 2, 1, 2, 1, 3, 2, 2, 1, 3, 1, 2, 2, 4, 1, 3, 1, 3, ... (Sloane's A001222). is plotted above up to (left) and (right).

The function defined by is known as the Liouville function.

An asymptotic series for is given by

(3)

(Diaconis 1976, Knuth 2000, Diaconis 2002, Finch 2003, Knuth 2003), where is a constant related to the Mertens constant and are Stieltjes constants. Furthermore, the variance is given by

(4)

where

(5)
(6)

(Sloane's A091589), and

(7)

(Sloane's A086242; Finch 2003) is a convergent prime sum. The coefficients and are given by the sums

Answer 5

36 = 2^2 X 3^2

40 = 2^3 X 5

90 = 2 X 3^2 X 5

Answer 6

36 is 6 x6
or more easily
2 x 2 x 3 x 3
that can be 2^2 x 3^2

40 breaks down as 10 x 4
and can further be 5 x 2 x 2 x2
Get it?

Answer 7

Its really very easy. You can do it for yourself dear