Help with solving this algebraic equation? Solve for A, B, and C.....[A/(s^2+1)] + [B/(s+1)] + [C/(s-1)] = 4?

Question

Again, the problem is [A/(s^2+1)] + [B/(s+1)] + [C/(s-1)] = 4
And I need to solve for A,B, &C
I know how to solve for B and C, but I can't get the answer to A.

Hi, so far, I've come up with B=1 and C=1. Also, the original question is a calculus question where we need to integrate 4/(s^4-1). I know what to do after solving for A. I took algebra a long time ago, so I'm clueless as to what partial fraction decomposition is, but thank you all for your responses so far :o)

Answer 1

if you have B and C, which you can solve for, you would have

A / (s^2 + 1) = 4 - (B/s+1) - (C/s-1).

A = [4 - (B/s+1) - (C/s-1)]*(s^2+1)

Answer 2

Are you doing partial fraction decomposition? If so, you need a denominator under the 4, and your numerator in the first term should be As+D.

Answer 3

-12 + x = 6 x = 6 + 12 ( pass 12 to different area of equasion, so replace it sign. ) x = 18 t - 7/4 = 8 t = 8 + 7/4 ( comparable rule as above ) t = 9 + 3/4 or ( 39/4 ) x - sixteen = -10 x = -10 + sixteen ( comparable rule lower back, pass to different area of equals sign so replace the sign ) x = 6 3x + a million = 5x - 10 ( could carry mutually 'x' words on one area ) 3x = 5x -10 -a million 3x - 5x = -10 -a million -2x = -11 -x = -11/2 ( pass a multiply on one area to the different so it differences to divide ) -x = -5.5 consequently x = 5.5 x / 5 - 4 = 2x / 5 + 6 (remember mathematical order. BODMAS brackets first, the operator ie powers. then divide then multiply then upload then subtract) carry mutually like words (x) on one area x/5 - 4 = 2x/5 + 6 x/5 = 2x/5 + 6 + 4 x/5 = 2x/5 + 10 -2x/5 + x/5 = 10 -x/5 = 10 -x = 10(5) -x = 50 x = -50

Answer 4

Are you trying to find the partial fraction decomposition of a rational expression? I will help you if I can.