how do you solve for variable a and b when give this equations:
angle4= 3a+b
angle5= 6a-14
angle6= -13b+3
P.S: please be very detailed so that i can how to solve it my self for future problems.
2006-10-03 06:52:09 · 4 answers · asked by coolkenny45 2 in Science & Mathematics ➔ Mathematics
angle 4 and 5 are supplementary but they dont have the same measurement. angel 4 and 6 are corresponding.
2006-10-03 07:10:57 · update #1
You need to know how angles 4, 5, 6 are related in order to solve this. Are they angles in a triangle? Do you have a picture? Are they all equal? Do you have the measures of any of the angles?
2006-10-03 07:01:48 · answer #1 · answered by raz 5 · 0⤊ 0⤋
Solve the second equation for a:
angle5+14=6a, so a=(angle5+14)/6.
Solve the third equation for b:
angle6-3=-13b, so b=(3-angle6)/13.
However, depending on the values given for angle4, angle5 and angle6, these values of a and b might not satisfy the first equation. The system of equations you describe is called an "overdetermined" system, because there are 3 equations and only 2 unknowns. Such systems may not have a solution.
2006-10-03 14:03:33 · answer #2 · answered by James L 5 · 0⤊ 0⤋
a4 = 3a + b
a5 = 6a - 14
top by 2 and subtract 2a4-a5 = 2b + 14
2b = 2a4-a5-14
together with a6=-13b+3.
solve for b, then for a.
rest for student to do
2006-10-03 14:09:58 · answer #3 · answered by rwbblb46 4 · 0⤊ 0⤋
I need more details...............angle of what????????
2006-10-03 14:04:16 · answer #4 · answered by Rita Z 2 · 0⤊ 0⤋