e^1-4x = 15
2006-10-03 06:40:51 · 5 answers · asked by pnoiz1 2 in Science & Mathematics ➔ Mathematics
e^(1-4x)=15
take logs of each side
(1-4x) =ln(15)
>>x = (1-ln(15))/4 = -0.4270(1)
therefore, x = -0.4270 to four decimal places
2006-10-03 06:59:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I assume you mean e^(1-4x) = 15.
Take the natural log of both sides:
ln e^(1-4x) = ln 15
=> (1-4x) ln e = ln 15
=> 1-4x = ln 15
=> 1 - ln 15 = 4x
=> x=(1-ln 15)/4
=> x=-0.4270, to four decimal places
2006-10-03 06:45:00 · answer #2 · answered by James L 5 · 0⤊ 0⤋
log base 10 and e are opposite of one yet another. So in case you multiply each and each aspect by skill of log, then the e will drop out. so that you'll have: 2x+a million= log 16 then remedy, utilizing a calc to approzimate.
2016-11-26 00:51:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋
e^1-4x = 15
take natural log on both sides
ln [e^1-4x] = ln15
1-4x = ln15 = 2.7080502
1-4x=2.7080502
1-2.7080502=4x
-1.7080502 = 4x
x=-0.42701255
x is -0.42701255
2006-10-03 07:10:13 · answer #4 · answered by Syed Baqir Rizvi 2 · 0⤊ 0⤋
Find it yourself.
2006-10-03 06:42:31 · answer #5 · answered by Emm 6 · 1⤊ 2⤋