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f(x) = a^x whose graph goes through the point (2,16).

a=


Thank you in advance.

2006-10-03 06:06:51 · 3 answers · asked by pnoiz1 2 in Science & Mathematics Mathematics

3 answers

Set x=2. Then a^2=16, so a=4.

2006-10-03 06:08:55 · answer #1 · answered by James L 5 · 1 0

a = 4

Solve for a by plugging in f(x) = 16 and x = 2

16 = a^2

Taking log on both sides,

you get a = (log 16)/(log 2) = 4

Exponential = 4^x

2006-10-03 13:09:59 · answer #2 · answered by JSAM 5 · 0 0

16=a^2
a=4

2006-10-03 13:11:09 · answer #3 · answered by rwbblb46 4 · 0 0

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