i need to find out the gradient of the line
2006-10-03 05:39:17 · 8 answers · asked by laura p 1 in Science & Mathematics ➔ Mathematics
5y=3-2x >>>>>y=3/5-(2/5)x
standard straight line >>>>> y= mx +c
where m= gradient
therefore,gradient = m = -2/5
(y intercept =3/5)
2006-10-03 05:55:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋
to locate the gradient of the immediately line, in simple terms convert your equation sort into y=mx+c format. 5y=3-2x will be switched over into y=(3/5)-(2/5)x through making y the concern through dividing both sideds through 5, therefore making the coefficient of x -2/5, so the gradient of the line of this equation will be -2/5...its a downward sloping line!
2016-12-04 04:16:33 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The gradient of a line is the slope. To get the slope, write the equation in the form y=mx+b. In this case, you get
y = (3/5) - (2/5)x
= -(2/5)x + (3/5)
so m=-2/5 and b=3/5. Therefore, the gradient is -2/5.
2006-10-03 05:42:48 · answer #3 · answered by James L 5 · 0⤊ 0⤋
gradient=-2/5
2006-10-03 06:04:07 · answer #4 · answered by faisal b 1 · 0⤊ 0⤋
5y=3-2x
y=3/5-2/5x
y=-2/5x+3/5
the gradient (slope) is -2/5
2006-10-03 05:41:23 · answer #5 · answered by Anonymous · 1⤊ 0⤋
y = m x + b
5y = 3 - 2x
5y = -2x +3
y = -2/5 x + 3/5 m = -2/5
2006-10-03 05:50:03 · answer #6 · answered by Brian D 5 · 0⤊ 0⤋
5y=x......so 45 degrees
2006-10-03 05:41:55 · answer #7 · answered by Anonymous · 0⤊ 1⤋
looks like you bettter read your text book again! :)
2006-10-03 05:41:37 · answer #8 · answered by just me being me 4 · 0⤊ 1⤋