Two painters working at the same speed can paint 800 square feet of wall space in 6 hours. If a third painter paints at the same speed how long will it take all 3 to paint the same wall space?
2006-10-03 04:05:25 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Each painter paints at a rate of 400 sq ft/6hrs = 66.7 sq ft / hr.
Time for 3 painters = (800 sq ft) / (3 * 66.7 sq ft per hr) = 4 hrs
2006-10-03 04:15:30 · answer #1 · answered by curious george 5 · 0⤊ 0⤋
Each worker can paint 400 square feet in 6 hours or 66 2/3 square feet per hour.
3 x 66 2/3 = 200 square feet per hour for three workers
It would take three painters 4 hours to do the work.
2006-10-03 04:09:51 · answer #2 · answered by Warren914 6 · 0⤊ 0⤋
2 do it in 6 hrs, hence 1 in 12 hrs, hence 3 in 12/3 = 4 hrs
however if you continue along this line 12 can do it in 1 hr and 72 can do it in 10 minutes etc
In real life when the 3rd guy joins the other two there will be a big argument about something with 2 against 1 and it will take longer than six hours
2006-10-03 04:16:21 · answer #3 · answered by wimafrobor 2 · 0⤊ 0⤋
Well, you can easily derive that one painter paints 400 square feet in 6 hours, or 66.67 square feet per hour.
If you have 3 painters, then together thay can paint 3 * 66.67 square feet per hours, or 200 square feer. You have 800 ft^2, so the 3 painters will have it done in 4 hours.
2006-10-03 04:07:58 · answer #4 · answered by Vincent G 7 · 1⤊ 1⤋
2p * 6 = 800
2p = 133.333
p = 66.66 so 3p * h = 800
h = 800 / 3(66.666) = 4 hrs
2006-10-03 04:12:19 · answer #5 · answered by Brian D 5 · 0⤊ 0⤋
4 hrs.
2006-10-03 04:10:51 · answer #6 · answered by nurseme0w 2 · 0⤊ 0⤋