pls help me to answer this....?

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What is the final concentration of 3.5 L of 2.3 molar acid solution when it is diluted to 5 L by adding more water?

pls help me answer this....

2006-10-03 01:49:36 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

This is easy:

(2.3 moles/liter) * (3.5 liters) = 8.05 moles

(8.05 moles)/(5.0 liters) = 1.61 M

2006-10-03 01:57:05 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋

Given: M1=2.3M; V1=3.5L;M2=?;V2=5L
so:
M1V1=M2V2
(2.3M)(3.5L)=M2(5L)
8.05ML = M2(5L)
5L 5L
M2=1.61M - the new concentration

2006-10-04 06:47:39 · answer #2 · answered by miaka y 2 · 0⤊ 0⤋