3x2 is supposed to be 3 times x squared. Is it possible that someone could help me factor this? I don't see how.
2006-10-03 00:48:55 · 8 answers · asked by fri_knight247 2 in Science & Mathematics ➔ Mathematics
3x2 is supposed to be 3 times x squared. Is it possible that someone could help me factor this? I don't see how.
I need to see the answer. I know what a quadratic equation is.
2006-10-03 01:00:42 · update #1
the equation cannot be factored.the roots will imaginary and irrational.the roots are x = (15 +/- sq. rt. of -195) / 6.
2006-10-03 01:01:02 · answer #1 · answered by salehm 1 · 0⤊ 0⤋
The quadratic formula stands as follows: y = -b + or - the square root of (b^2 - 4 times a times c) all divided by 2 times a. In your case a = 3, b = 15, and c = 35. Try solving that equation with the ones that is given.
2006-10-03 03:37:39 · answer #2 · answered by jlpman5000 2 · 0⤊ 0⤋
In real space, the equation has no solution. Using the b^2 - 4ac test, you find -195 < 0.
Don't know if you want to use complex numbers, but then
(x - 2,5 - i*sqrt(195)) (x - 2.5 + 1*sqrt(195))
[ i being the complex sqrt(-1) ]
2006-10-03 00:59:22 · answer #3 · answered by wernisch 2 · 0⤊ 0⤋
b^2- 4ac = 15^2-4*3*35 = 225-420 = -195
so this does not have real roots.So cannot be factored in real domain
there are complex roots only
they are (-b+sqrt(b^2-4ac))/2a and (-b-(sqrt(b^2-4ac)/2a
= (15+sqrt(-195))/6(say a) and (15-sqrt(-195))/6(say b)
the factors are
(x-a)(x-b) where a and b area as above
2006-10-03 00:54:36 · answer #4 · answered by Mein Hoon Na 7 · 0⤊ 1⤋
It's a quadratic equation. However, this one doesn't have a solution in the real numbers.
2006-10-03 00:56:31 · answer #5 · answered by nondescript 7 · 0⤊ 1⤋
3x² - 15x + 35
No Solution
2006-10-03 04:58:08 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
You might have copied the Q wrong
2006-10-03 00:59:33 · answer #7 · answered by Haru 1 · 0⤊ 0⤋
use formula
x= {-b +/- (b^2- 4ac)}/2a
2006-10-03 00:58:59 · answer #8 · answered by Nick 3 · 0⤊ 0⤋