2006-10-02 21:05:10 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
what?
2006-10-06 05:57:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let (x,y) be the reqd co-ordinate
We know,
x = {mx2 + nx1}/ (m+n) and y = {my2 + ny1}/(m+n)
[ Here ,x1 = 3, y1 = -4, x2 = 5, y2 = -7, m = 2 and n = 3 ]
putting the above values , we get
x = 19/5 =3.8 and
y = - 26/5 = -5.2
2006-10-02 22:19:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Let P(x,y) be the reqd co-ord.
now
x = {mx2 + nx1}/ (m+n) and y = {my2 + ny1}/(m+n)
Now x1 = 3, y1 = -4, x2 = 5, y2 = -7, m = 2 and n = 3
hence, x = 19/5 and y = - 26/5
2006-10-02 21:48:24 · answer #3 · answered by mr_BIG 3 · 1⤊ 0⤋
coordinates are (19/5,-26/5)
2006-10-02 21:14:07 · answer #4 · answered by neeti 2 · 0⤊ 0⤋
(19/5,-26/5) .
2006-10-02 21:25:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋
You will never learn letting others do your homework.
2006-10-02 21:28:52 · answer #6 · answered by Anonymous · 0⤊ 1⤋
x=(2*5+3*3)/(2+3)=19/5,
y=(2*-7+3*-4)/(2+3)=-26/5;
Hance the answer of your question is(19/5,-26/5).
Thanks
2006-10-02 23:41:05 · answer #7 · answered by j-11 1 · 0⤊ 0⤋
(19/5, -28/5).
VR
2006-10-02 21:21:35 · answer #8 · answered by sarayu 7 · 0⤊ 0⤋
x=(mx[2]+nx[1])/m+n
y=(my[2]+ny[1])/m+n
x=19/5
y=-26/5
2006-10-06 07:15:36 · answer #9 · answered by SIVA R 1 · 0⤊ 0⤋
(3.8, -5.2)
Doug
2006-10-02 21:16:11 · answer #10 · answered by doug_donaghue 7 · 0⤊ 0⤋