solve by using subtitution
2006-10-02 19:47:03 · 5 answers · asked by mylipshot 2 in Education & Reference ➔ Homework Help
3x-9=-10
3(x-3)=-10
x-3=-3.33
x=-3.33+3
x=-0.33
sub X
3y=-0.33+5
3y=4.66
y=1.55
2006-10-02 19:55:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3y = x+5 3x-9 = -10
3x-9 = -10
3x = -10+9
3x = -1
x = -1/3
3y = x+5
3y = -1/3+5
3y(3) = (-1/3) (3) + 5*3
9y = -1+15
9y = 14
y = 14/9
y = 1.55
2006-10-03 12:11:37 · answer #2 · answered by Wanlaya 3 · 0⤊ 0⤋
3x-9=-10
3x=-10+9
3x=-1
divide both sides by 3, thus remaining x in one side
x= -1/3
substituting x in the equation:
3y=x+5
3y=-1/3+5
3y= -4.67
y=1.56
2006-10-03 03:59:19 · answer #3 · answered by ms. carpenter 2 · 0⤊ 0⤋
3x-y=-10
3y-x=5
multiply seecond equation by 3
3x-y=-10
9y-3x=15
by substracting them:
8y=5, y=8/5
x=-58/5
answer
2006-10-03 03:04:40 · answer #4 · answered by nicefriendvikas 3 · 0⤊ 0⤋
guess there is some typing error, check and add additional detail
2006-10-03 07:30:19 · answer #5 · answered by hmmm 3 · 0⤊ 0⤋