If you use the form q = kA(T2-T1) and perform dimensional analysis on it, you would arrive at the units of k = W/(m^2*K). But do these units hold true in the differential form? dT/dt = -k(T2-T1)?
2006-10-02 18:56:51 · 2 answers · asked by JoeSchmo5819 4 in Science & Mathematics ➔ Chemistry
The differential form I used is just another form of writing the law. dTemperature/dtime = alpha(T2-T1). I was just trying to figure out if the constant in the one form was the same units as the constant in the other. Tnx.
2006-10-03 05:35:06 · update #1
I answered this question in Physics, where you asked it 2 hours ago.
2006-10-02 19:03:12 · answer #1 · answered by Frank N 7 · 1⤊ 0⤋
yes, they do, for k. what you've written for a differential doesn't make much sense, but there would have to be some time unit on the RHS to make it work. The derivative dq/dt would imply that something on the RHS is changing with time, most likely one of the temperatures, so
dq/dt = kAdT2/dt, for example.
2006-10-02 19:02:27 · answer #2 · answered by arbiter007 6 · 0⤊ 0⤋