Given the sequence of integers where every third term is a multiple of 3 and every second term is a multiple of two. which of the following could be the value of the 144th terms in the sequence. Please show work and explain your method.
a. 15
b. 44
c. 81
d. 114
e. 206
2006-10-02 18:38:35 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
the 144 term must be divisible by 2 as well as by 3 and the only number on that list that meets those requirements is 114, so d must be your answer
2006-10-02 18:42:47 · answer #1 · answered by piggip05 2 · 0⤊ 0⤋
Since it is the 144th term, is should be divisible by 2 and 3, and 114 is the only number that fit with the conditions above.
2006-10-03 02:35:08 · answer #2 · answered by tombraider 3 · 0⤊ 0⤋
Call the term number "n". That makes the first term n1, the second n2, the third n3, etc. Call the integer associated with n "x". So, the integer that n1 is associated with is x1, n2 is x2, and so on.
If n is divisible by 3, x is also divisible by 3. If n is divisible by 2, x is also divisible by 2. 144 is divisible by 2 and 3, so it follows that x144 will be divisible by both.
d. 114 is the only answer that is divisible by 2 and 3.
2006-10-03 01:44:41 · answer #3 · answered by Kat 2 · 0⤊ 0⤋
144=3^2*2^4
So the 144th term in sequence is a multiply of 2 and 3. only 144 can divide into 6. so it’s one I choose.
2006-10-03 02:00:00 · answer #4 · answered by helix 1 · 0⤊ 0⤋
i think is 114 itself. like 3 for every third, and 2 for every second.
3 goes into 3 one time, 6 two times, 9 three etc. and 2 goes in to 2 once and 4 twice, so 114th goes in to 114 once...
2006-10-03 01:44:53 · answer #5 · answered by tjdeya24 2 · 0⤊ 0⤋
it must be both multiple of 2 and 3.
The answer is d. 114
2006-10-03 01:58:11 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋
get some paper and try to figer it out yourself. I am not doing your homework for you. If you really need help ask your parents or teachers
2006-10-03 01:41:05 · answer #7 · answered by Sekkennight 3 · 1⤊ 1⤋