The perimeter of a rectangle is 162 ft. The lenght is 3 more than twice the width. Find the dimensions of the rectangle.
I kknow the first equation is 2L+2W=162 but i have no idea what the second equation is
(using sysytems of equation)
2006-10-02 16:03:50 · 6 answers · asked by Mia16 3 in Science & Mathematics ➔ Mathematics
Right p=2l+2w=162
the 2nd is:
l=3+2w
substitute:
162=2(3+2w)+2w
162=6+4w+2w
156=6w
w=26
l=3+2w=3+2*26=55
check:
162=2*55+2*26=110+52=162
2006-10-02 16:10:17 · answer #1 · answered by yupchagee 7 · 16⤊ 0⤋
eq.1 2L + 2W = 162 2L + 2W = 162
eq.2 L = 2W + 3 becomes L - 2W = 3
add the 2 equations, you'll have
3L = 165
divide both sides by 3,
L = 55
substitute the value of L in eq.1,
2(55) + 2W = 162
110 + 2W = 162
2W = 162-110
2W = 52
W = 26
answer: L=55, W=26
2006-10-02 23:13:27 · answer #2 · answered by kezongputi 2 · 0⤊ 0⤋
L = 2w + 3
2006-10-02 23:16:01 · answer #3 · answered by CP 4 · 0⤊ 0⤋
All right,
twice the width: 2W.
three more than twice the width: 2W + 3.
"The length is three more than twice the width": 2W + 3 = L.
Understand?
Good. Show me.
HTH.
2006-10-02 23:06:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋
l=2w+3(3 more than twice the width)
2(L+W)=162
2(2w+3+w)=162
3w+3=81
3w=78
w=26
l=2(26)+3
l=52+3
l=55
w=26ft l=55ft
2006-10-02 23:09:40 · answer #5 · answered by Croasis 3 · 0⤊ 0⤋
let 3+2x= length
let x = width
2(3+2x)+2x=162
2006-10-02 23:08:44 · answer #6 · answered by ghostychick88 2 · 0⤊ 0⤋