Sailboat Speed. The sail area-displacement ratio S provides a measure of the sail power available to drive a boat. For a boat with a displacement of d pounds and a sail area of A square feet. S=16Ad^-2/3
a) Find S to the nearest 10th for the Tartan 4100, which has a sail area of 810 square feet and a displacement of 23,245 pounds
b) Solve the formula for d
2006-10-02 15:53:50 · 2 answers · asked by racheldawnsmith311 1 in Science & Mathematics ➔ Mathematics
a)
S=16(810)(23245)^2/3
S=16(810)(0.00123)
S=15.9 <-to the tenth
b)
S=16A/d^2/3
Sd^2/3 = 16A
d^2/3=16A/S
d=(16A/S)^3/2
2006-10-02 16:03:25 · answer #1 · answered by Anon 2 · 1⤊ 0⤋
A=810, d=23,245, so S=15.9.
Solving for d: rearrange, then raise both sides to the -3/2 power:
S/(16A) = d^(-2/3)
so
d=(S/(16A))^(-3/2).
2006-10-02 15:57:19 · answer #2 · answered by James L 5 · 0⤊ 0⤋