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The sum of two numbers is 104. the larger number is 1 less than twice the smaller number. Find the numbers.

2006-10-02 15:46:13 · 7 answers · asked by Mia16 3 in Science & Mathematics Mathematics

7 answers

let x be the smaller no.
let 2x-1(1 less than twice the other number which is x) be the larger no.

x+2x-1=104
3x-1=104
3x=105
x=35

2(35)-1
70-1
69

35 and 69

35+69=104

2006-10-02 15:50:32 · answer #1 · answered by Croasis 3 · 0 0

system of equations is just putting word problems into equations, then using them to solve for the answers. Just use leters to represent the unknown numbers.

The sum of two numbers is 104.
x + y = 104

The larger number is 1 less than twice the smaller number. Pick x to be the larger number and write how they relate, the larger (X) is 1 less than 2 times the smaller (y).

x = 2y -1


To find the numbers, insert the value of x as 2y-1 into the first equation:

(2y -1 )+ y = 104 Then solve for Y. Once you have y you can insert that value and find X

2006-10-02 16:08:06 · answer #2 · answered by CP 4 · 0 0

Let x be the smaller number. Then, the larger number is 104 - x.

Using the second part of your statement, the larger number is 1 less than twice the smaller number, we get

104 - x = 2x - 1

Now solve for x by rearranging and collecting like terms. Once you have x, you can easily find the larger number as well.

2006-10-02 15:49:13 · answer #3 · answered by whatthe 3 · 0 0

The larger no. is 69. The smaller no. is 35.

2006-10-02 15:49:58 · answer #4 · answered by mathlete1 3 · 0 0

let x=larger # & y=smaller #

x+y=104
x+1=2y
x=2y-1
substitute:
2y-1+y=104
3y=105
y=35
x=2y-1=2*35-1=70-1=69.
35+69=104

2006-10-02 16:18:07 · answer #5 · answered by yupchagee 7 · 0 0

x +y = 104 x>y
x = 2*y-1
y =35
x = 69

2006-10-02 15:48:47 · answer #6 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0 0

do you know how to formulate the equation? assign a variable x or y to each unknown value. then make 2 equations...
x-1=2y
x+y=104
SOLVE

2006-10-02 15:49:37 · answer #7 · answered by blood 2 · 0 0

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