How do you change the equation y=Vyt+1/2at^2 to solve for time?

Question

If I have y= -10m,Vy=0,and a = -9.8m/s^2. Need to solve for t or time?

I still don't understan how to get the answer?

Istill don't understand how i can get the time if i have y= -10m, Vy=0, and if the a -9.8m/s^2.

Answer 1

you would have to use the quadratic formula

Answer 2

-10m=(1/2)(-9.8m/s^2)t^2
t^2 = approx 2.04

t= approx radical 2
t= approx 1.41

(you can disregard the (Vyt ) because Vy is zero so Vyt=0

Answer 3

1/2at^2+Vyt-y=0

This is a quadratic equation of the form At^2 Bt+C where A=1/2a,
B=Vy and C=-y

Now use the quadratic formula:
t={-B +or- radical(B^2-4AC)}/2A (radical means take square root of expression in side the parentheses.

t={-Vy + or - Square root of (V^2y^2 -4(a/2)(-y))}/2(a/2)
t={-Vy + square root of (V^2y^2 +2ay)}/a
t={-Vy - square root of (V^2y^2 +2ay)}/a

So there are two values of t.

Answer 4

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