shaw cable broadbent....can't get rid of AOL dial-up....keeps going to it....cable internet already open
2006-10-02 14:45:40 · 9 answers · asked by jennita 1 in Computers & Internet ➔ Internet
ALSO, go to Internet Options, and go to CONNECTIONS. Then pick the option NEVER DIAL A CONNECTION.
Yes, uninstall AOL if you are DONE. But if you continue to use AOL, then get into setup and add a NETWORK connection, since you do not need to Dial Up anymore.
2006-10-02 14:50:27 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Uninstall AOL. Go to Control Panel, then go to Add Remove Programs and never install anything that has to do with AOL. It hogs all your memory and tries to take over you system.
2006-10-02 14:57:10 · answer #2 · answered by Toni J 1 · 1⤊ 0⤋
Control Panel > Add/Remove Programs > uninstall that AOL garbage
2006-10-02 14:47:22 · answer #3 · answered by Lloyd 5 · 2⤊ 0⤋
Delete aol junk
2006-10-02 14:49:36 · answer #4 · answered by roeroe47me 3 · 1⤊ 0⤋
Call AOL and tell them you no longer need their service.
They will probably offer you FREE TIME ...but you don't really need it with cable.
1. And don't forget to go to the remove file in add & remove.
TO REMOVE:
1.Go to Start
2. Settings
3.Control panal
4. Add Remove
5. Scroll till you see AOL
click on remove...and wala, it will remove AOL and all it's componets.
You may have to restart your computer for it to take effect.
2006-10-02 14:48:34 · answer #5 · answered by tbrat2u 2 · 1⤊ 1⤋
Open Internet Explorer, go to Tools, then Internet Options, then go to the Connections Tab, then select the radio button that says "Never dial a connection." Then click OK.
This should resolve the issue for you!! :-)
2006-10-02 14:48:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
reinstall aol, if u dont have a disk u can do from the site and it will change it all for just follow the steps to so
2006-10-02 14:48:01 · answer #7 · answered by DONALD L 2 · 0⤊ 2⤋
un install aol
2006-10-02 14:48:19 · answer #8 · answered by Backwoods Barbie 7 · 0⤊ 0⤋
sorry LOL
2006-10-02 14:48:11 · answer #9 · answered by jonathan k 1 · 0⤊ 2⤋