The lengths of the edges of a cube are increased y 20%. The surface area and volume increases by what percent

Question

Basic geometry question,

Answer 1

So to start with we need to set the basic formulas:

S(x)=surface area
S(x)=6x^2

V(x)=volume
V(x)=x^3

Now take your new side length, 1.2x, and place it in for x.

S(1.2x)=6(1.2x)^2
=6*1.44x^2
=8.64x^2

Therefore, the percent increase in surface area is:
8.64x^6 8.64
------------ -1 = ------ -1 = 1.44 -1 = 44%
6x^2 6

V(1.2x)=(1.2x)^3
=1.728x^3
Therefore, the percent increase in volume is:
1.728x^3
------------ -1 = 1.728 -1 = 72.8%
x^3

So your final answer is an 44% increase in surface area and a 72.8% increase in volume.

Answer 2

area = side squared
volume = side cubed

(1.2)^2 = 1.44, so the area increases 44%
(1.2)^3 = 1.728, so the volume increases 72.8%

Answer 3

1.2 x 1.2 = 1.44
Surface area increases by 44%

1.2 x 1.2 x 1.2 = 1.728
Volume increases by 72.8%

Answer 4

enable A1 = unique floor section A2 = better floor section % boost = (A2 – A1) / A1 A1 = 6s^2 A2 = 6(a million.50s)^2 = 6(2.25)s^2 = thirteen.5s^2 % boost = (A2 – A1) / A1 = (thirteen.5 s^2 - 6s^2) / 6s^2 = 7.5s^2 / 6s^2 = a million.25. or one hundred twenty 5%

Answer 5

sa = 1.2*1.2 * 6 = 44%

Volume = 1.2*1.2*1.2 = 72.8%