A man is running in a straight line. The distance (in meters) he has travelled from home is described by the equation.
s(t) = 8t^2 + 7t + 5
t is time in minutes. Find the average velocity of the man over the time interval (2.5, 3.5)
And for part B What is the instantaneous velocity at t=2
2006-10-02 14:09:50 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The average velocity is given by
[s(3.5) - s(2.5)] / (3.5-2.5) = (127.5 - 72.5) / 1 = 55 m/min.
The instantaneous velocity at t=2 is given by s'(2), where s'(t) = 16t + 7, so s'(2) = 39.
2006-10-02 14:15:04 · answer #1 · answered by James L 5 · 0⤊ 0⤋
been a while for these kind of equations ...
δs(t)/δ(t)= 16t+7
therefore s(2.5) = 47
s(3.5) = 63
Average = 55 (something is not quite right about this ...)
@ s(2) = 39 metres/minute
2006-10-02 21:33:58 · answer #2 · answered by lx470_98 1 · 0⤊ 0⤋