2x^4-26x^3-96x^2
3x^4+54x^3+135x^2
3x^2+8x+5
2x^2+9x+7
5x^2+56x+11
5x^2-16x+3
3y^2+22y-16
5y^2+33y-14
4y^2+9y+2
8y^2+10y+3
10x^2+19x+6
6x^2+19x+15
8x^2-18x+9
4x^2-27x+18
6y^2-23y+15
16y^2-6y-27
6y^2+14y+3
4y^2+22y-5
2006-10-02 12:53:59 · 7 answers · asked by Sarah M 2 in Science & Mathematics ➔ Mathematics
I need to factor each of these problems and it takes forever for me to do it myself and I am wondering if someone would give me the damn answers!
2006-10-02 13:10:57 · update #1
I DON'T WANT TO KNOW HOW TO DO IT! I ALREADY KNOW HOW IT DO IT! I JUST WANT SOMEONE TO SAVE ME ALL THE TIME OF DOING IT MYSELF AND GIVE ME THE ANSWERS! ANSWERS! ANSWERS! ANSWERS! ANSWERS!
2006-10-02 13:23:29 · update #2
I wont give you the answers but I'll show you an easy way to do them.
Like for 2x^3 + 6x^2 + 4x.
You can see that they all have an x in common, so take that out first.
x(2x^2 + 6x + 4)
So now you have a quadratic equation.
So find two numbers that multipy to 8 that add to 6. It would be 2 and 4.
So now rewrite your equation, dont forget the x on the outside!
x(2x^2 + 2x + 4x +4)
x [ 2x(x + 1) + 4 (x + 1) ]
x (x + 1) (2x + 4)
There you go!
2006-10-02 13:26:41 · answer #1 · answered by teekshi33 4 · 0⤊ 0⤋
to start, these are her homework ... just a list of algebraic questions, all = 0
The first one ... divide by x^2 ... that is, x=0 twice, then simplify by dividing by 2 ... leaving
x^2 - 13x -48 =0
have a lok, work out the factors for 48:
2/24
3/16
4/12
6/8
which combination gives you 13 ...
(x-16)(x+3)
x=16 or x = -3 or x=0
2006-10-02 13:07:50 · answer #2 · answered by lx470_98 1 · 0⤊ 0⤋
Take x^2 common from the expression & factorise in normal way as in quadratic expression.for example,the first is
Step:1; x^2(2x^2-26x-96)
step:2; x^2(2x^2-32x+6x-96) {-26=-32+6}
step:3; x^2(x-16)(2x+3) [answer]
2006-10-02 13:20:33 · answer #3 · answered by ashok r 1 · 0⤊ 0⤋
giggling and crying are the two an emotional launch. I cry over no longer something. Then there are days i myself desire to observe a humorous movie and basically chuckle. I desire to try this with buddies yet on my own works nicely additionally. existence is stressful now and that i'm no longer getting any help from my husband. He basically throws each and every thing my way and then expects me to be sympathetic to him. i comprehend what you recommend approximately drained.
2016-10-18 09:23:55 · answer #4 · answered by ? 4 · 0⤊ 0⤋
What exactly are you looking for us to help you with?
I have analyzed this message, and my analysis shows that there are a lot of algebraic expressions. What is the question?
2006-10-02 13:01:04 · answer #5 · answered by whatthe 3 · 0⤊ 0⤋
www.quickmath.com, click on Factor under Algebra, then type in your problem, and it will factor it for you.
2006-10-02 14:24:08 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
wow. i bet that took you ages to type up.
2006-10-02 12:55:44 · answer #7 · answered by need help! 3 · 0⤊ 0⤋