EACH SIDE NEEDS TO BE EQUVIALENT TO THE OTHER
2006-10-02 12:36:16 · 14 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Another question for your "niece"?
Put all the x terms on one side and all the integers on the other side.
Then solve for x.
Easy-peasy!
2006-10-02 12:38:36 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 0⤋
X=3
2006-10-02 21:24:03 · answer #2 · answered by Amanda G 2 · 0⤊ 0⤋
5x + 2x -4 = 4x = 5
Move all x terms to the left and all constants to the right
Moving terms will change their signs (+ to - or - to +)
5x + 2x - 4x = 5 + 4
Add all terms
3x = 9
Solve for x
x = 9 / 3
x = 3
Substituting 3 for all values of x in the original equation
5(3) + 2(3) - 4 = 4(3) + 5
15 + 6 - 4 = 12 + 5
17 = 17
x = 3 makes the equation equivalent
2006-10-02 19:45:33 · answer #3 · answered by Redhawkphl 2 · 0⤊ 0⤋
5x + 2x - 4= 4x+ 5
7x - 4 = 4x +5
-4x -4x
3x -4= 5
+4 +4
3x= 9
x= 3
2006-10-02 19:41:41 · answer #4 · answered by bri 2 · 0⤊ 0⤋
x=3
2006-10-02 19:39:57 · answer #5 · answered by Richard H 2 · 0⤊ 0⤋
You'd add 5x+2x which is 7x
7x-4=4x+5
Then you'd take the 4 from the left and add it to the 5 on the right
7x=4x+9
Then you subract take the 4x from the right and subract it from the 7x on the left
3x=9
then take the 3 from the 3x and divide the 9 by it.. 9 divided by 3 is 3.. so
x=3
2006-10-02 19:46:03 · answer #6 · answered by DoConway 1 · 0⤊ 0⤋
5x +2x = 7x
7x-4 = 4x+5
add four to both sides of the equation
7x = 4x +9
subtract 4x from both sides of the equation
3x = 9
divide both sides by 3
x=3
2006-10-04 20:30:05 · answer #7 · answered by Becca 3 · 0⤊ 0⤋
5x + 2x - 4 = 4x + 5
5x + 2x - 4x = 5 + 4
7x - 4x = 9
3x = 9
x = 3
2006-10-02 19:47:46 · answer #8 · answered by Hunk J 1 · 0⤊ 0⤋
7x-4=4x+5
x=3
2006-10-02 19:46:54 · answer #9 · answered by Anonymous · 0⤊ 0⤋
7x -4 = 4x +5
3x=9
x=3
2006-10-02 19:44:32 · answer #10 · answered by i must be bored, im on Y answers 3 · 0⤊ 0⤋
solution
collect like term
5x+2x-4x=5+4
7x-4x=9
3x=9
divide both side by 3
3/3=9/3
x=3 answer
2006-10-02 19:54:09 · answer #11 · answered by azemheobor4real 1 · 0⤊ 0⤋