2006-10-02 11:29:31 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(x^2 - 8x) = sqrt(x^2 + 8x)
since both sides have sqrt, the sqrts cancel out
x^2 - 8x = x^2 + 8x
x^2 - 8x - x^2 - 8x = 0
-16x = 0
x = 0
ANS : 0
2006-10-02 11:53:07 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
Since this implies x^2-8x = x^2+8x
which implies -8x = 8x, or 16x = 0,
the only possible solution is x = 0.
2006-10-02 11:37:41 · answer #2 · answered by David Y 5 · 0⤊ 0⤋
you should do ur own homework but im being nice and telling you the answer its 0
2006-10-02 11:42:14 · answer #3 · answered by iluvmypuppy 2 · 0⤊ 0⤋
have you ever said the question suited ? what's the coefficient of x² ? Is it ab or 4ab ? Is the finest time period - bc or - 4bc ? Please be confident the question and state it suited.
2016-11-25 23:19:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Do your own homework.
2006-10-02 11:36:43 · answer #5 · answered by aint_no_stoppin_us 4 · 0⤊ 1⤋
THANK YOU! for doing your own homework.
2006-10-02 11:36:20 · answer #6 · answered by Anonymous · 0⤊ 1⤋