2006-10-02 10:47:48 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
substitute x by -2:
5x2 - 3x(-2) + 1 = 10 + 6 + 1 = 17
2006-10-02 10:58:54 · answer #1 · answered by Guy VS 4 · 0⤊ 1⤋
put a -2 everywhere ther is an X
so 5*-2*2 -(3*-2)+1 = -20 - (-6) +1 = -20+6+1 = -20+7 = -13
dear lord where did the first 2 people go to school?
2006-10-02 10:58:03 · answer #2 · answered by Liz 3 · 0⤊ 0⤋
27
2006-10-02 10:50:22 · answer #3 · answered by statstastic 2 · 0⤊ 1⤋
27
2006-10-02 10:50:05 · answer #4 · answered by Anonymous · 0⤊ 1⤋
f(x) = 5x2 - 3x + 1
f(-2) = 5(-2)2 - 3(-2) + 1
f(-2) = -20 + 6 + 1
= -13
2006-10-02 10:52:33 · answer #5 · answered by JennyAnn 4 · 1⤊ 0⤋
5(-2) ^ 2 - 3(-2) + 1
5(4) - (-6) + 1
20 + 6 + 1 = 27.
2006-10-03 04:20:26 · answer #6 · answered by jlpman5000 2 · 0⤊ 0⤋
Just substitute the -2 for the x's:
5(-2)(-2) - 3(-2) + 1
Now multiply and watch out for the negative signs. Your answer will be positive when you multiply two negatives.
2006-10-02 10:50:40 · answer #7 · answered by tlf 3 · 0⤊ 1⤋
f(-2)= -13 if you mean f(x)=(5)*(x)*(2)-(3)*(x)+1
or
f(-2) = 27 if you mean f(x) = (5)*(x raised to the 2nd power)-3(x)+1
or
f(-2) = 15 if you mean f(x)= (5)*(2) – 3x + 1
2006-10-02 10:56:52 · answer #8 · answered by krypt0n1an 1 · 1⤊ 0⤋
If you do a search for google calculator, you can input whatever you want and when you hit enter it will give the answer. Not 100% sure if it works for calculus though.
2006-10-02 10:52:58 · answer #9 · answered by bobdabuilr 2 · 0⤊ 0⤋
f(x)=5x^2-3x+1
f(-2)=5(-2)^2-3(-2)+1
f(-2)=5*4+6+1
f(-2)=20+6+1=27
2006-10-06 09:57:10 · answer #10 · answered by yupchagee 7 · 0⤊ 0⤋