What is the find the width of the rectangle?
2006-10-02 10:27:30 · 6 answers · asked by brandywine614 1 in Science & Mathematics ➔ Mathematics
The width is x. The length is 2x + 9. The perimeter is therefore x + x + 2x + 9 + 2x + 9 = 6x + 18 = 42. You should be able to solve this using simple algebra to find x, the width.
2006-10-02 10:29:54 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Let the width be x. Then the length is 9+2x.
Perimeter is length + length + width + width
42=9+2x+9+2x+x+x
Collect like terms.
42=18+6x
Now solve for x
24=6x
x=4
Thusly the width is 4 inches
2006-10-02 17:31:14 · answer #2 · answered by whatthe 3 · 0⤊ 0⤋
w=4
2006-10-02 17:30:19 · answer #3 · answered by bflo73 1 · 0⤊ 0⤋
l = 2w + 9
P = 42
P = 2(l + w)
42 = 2((2w + 9) + w)
42 = 2(2w + 9 + w)
42 = 2(3w + 9)
42 = 6(w + 3)
7 = w + 3
w = 7
l = 2(7) + 9 = 14 + 9 = 23
Length = 23in
Width = 7in
ANS : 7 inches
2006-10-02 19:33:34 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
l=9+2w
2(l+w)=42 so 2w + 2(9+2w)=42 so 2w+18+4w=42 so 6w=24 so w=4 so l=17
2006-10-02 17:31:48 · answer #5 · answered by daniel_cohadier 3 · 0⤊ 0⤋
w=4in
2006-10-02 17:53:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋