Given f(x) = –x3 + 2x2 + 2x – 9, find f(–1), f(0), and f(1)?

Question

I cannot figure this out,anyone help me?

Answer 1

f(-1)= -8
f(0)= -9
f(1)= -6
u just replace the numbers in the equation

Answer 2

I. -(-1)^3 + 2(-1)^2 + 2(-1) - 9
1 + 2 + -2 - 9
3 + -11 = -8

II. -(0)^3 + 2(0)^2 + 2(0) - 9
0 + 0 + 0 - 9 = -9

III. -(1)^3 + 2(1)^2 + 2(1) - 9
-1 + 2 + 2 - 9
-1 + 4 - 9
3 - 9 = -6

Answer 3

f(-1) = -(-1)^3 + 2(-1)^2 + 2(-1) - 9
f(-1) = -(-1) + 2(1) - 2 - 9
f(-1) = 1 + 2 - 11
f(-1) = 3 - 11
f(-1) = -8

f(0) = -(0)^3 + 2(0)^2 + 2(0) - 9
f(0) = -9

f(1) = -(1)^3 + 2(1)^2 + 2(1) - 9
f(1) = -(1) + 2(1) + 2 - 9
f(1) = -1 + 2 - 7
f(1) = 1 - 7
f(1) = -6

Answer 4

all you do is plug in those numbers for x. so plug in -a million to each and every x and locate the answer. then plug in 0 for each x and locate the answer. then plug in a million for each x and sparkling up. Its extremely effortless