2006-10-02 10:17:59 · 7 answers · asked by brandywine614 1 in Science & Mathematics ➔ Mathematics
f(a + 3) = 2(a + 3) + 4
= 2a + 6 + 4
= 2a + 10
* What the hell is Donovan doing? Donovan set up the expression as an equation that equals nothing, and then he subtracted the 10 to the other side! Makes no sense at all. Then Melanie G copied his wrong answer. What are algebra 2 teachers teaching these days?
2006-10-02 10:19:33 · answer #1 · answered by عبد الله (ドラゴン) 5 · 1⤊ 0⤋
f(x) = 2x + 4
f(a + 3) = 2(a + 3) + 4
= 2a + 6 + 4
= 2a + 10
2006-10-03 11:28:04 · answer #2 · answered by jlpman5000 2 · 0⤊ 0⤋
For the x, replace it with (a+3)
2(a+3)+4
2a+6+4
2a+10
2a=-10
a=-5
2006-10-02 18:06:40 · answer #3 · answered by Melanie G 1 · 0⤊ 0⤋
2(a+3)+4=
2a+10=
2a+10-10= -10
2a=-10
divide each side by 2
f(a)= -5
may or may not be right. did problems like this last year in Algebra 2.
2006-10-02 17:27:56 · answer #4 · answered by Donovan G 5 · 0⤊ 0⤋
f(a+3)=2(a+3)=4
f(a+3)=2a+6+4
f(a+3)=2a+10
f(a+3)=2(a+5)
The first and second answers are correct. As well as mine.
2006-10-02 17:25:54 · answer #5 · answered by Devin 2 · 0⤊ 0⤋
Go with the first answer. Looks good to me.
EDIT: 3rd and 7th answers are WRONG! You are not SOLVING for anything. You are simplifying, which is different.
2006-10-02 17:26:24 · answer #6 · answered by powhound 7 · 0⤊ 0⤋
go with the third answer
2006-10-02 22:34:06 · answer #7 · answered by Inya 3 · 0⤊ 0⤋