I need to know how to make these equations balanced any help would be great?

Question

O3-->O2

Cu + AgNO3-->Cu(NO3)2(aq) + Ag

Fe+ O2--> Fe203

NH3+O--> NO2+ H2O

Answer 1

2O3-.3O2

Cu + 2AgNO3 -> Cu(NO3)2 +2Ag

4Fe + 3O2 -> 2Fe2O3

4NH3 +7O2 -> 4NO2 +6H2O

Answer 2

ooh ohh I might be wrong but I just learned that too k here goes:
O3-->O2 Ok to balance this, you times the 3 by the 2 and the 2x3 so, you put a line thingy infront of the start of each element and you put that number you times it by where the line is. That way, they are balanced by 6!

Cu + AgNO3--> Cu(NO3)2(aq)+ Ag

Ok so for this one, first put the lines in the front of each start of the element. Like this:

_Cu + _AgNO3--> _Cu(NO3)2(aq)+ _Ag

K, then you look at Cu and the Cu on the other side. this one needs to be balanced because there is a 2 outside the bracket!
So you make the Cu balanced. Put the two infront of the first Cu to make sure it's balanced. Then look at Ag. Those are balanced so you don't do anything.

And i'm not sure but now since the Cu has a number of 2, you have to make the NO3 the same so it's balanced out. So you put a 2 infront of the 1st Ag & 2nd Ag and this is what it should look like after all that:
2Cu + 2AgNO3--> Cu(NO3)2(aq)+ 2Ag

I might not be right but that's how I learned it good luck!!

Answer 3

2o3-------3o2

Cu + 2AgNO3 ------- Cu(NO3)2 +2Ag

4Fe + 3O2-------- 2Fe2O3

4NH3 +7O2 ------- 4NO2 +6H2O

you must sure that every element equals in both side of equation

so, in first equ. you have 3 molecule of o and 2in the other so you must have the same no.

you multiplied o3 by2 and o2by3

Answer 4

203-->302
cu +2AgNO3-->Cu(NO3)2 +2Ag
4Fe+ 3O2-->2Fe2O3
2NH3 + 7O-->2NO2 + 3H2O