I worked out that the first derivative was 1 over 1 - cosx, but my calculator says something different, 1 over cosx - 1. Help?
2006-10-02 09:35:09 · 4 answers · asked by velmakelly777 1 in Science & Mathematics ➔ Mathematics
I got the first derivative as:
(cosx - 1)/(1-cosx)²
So, the second derivative that I got was:
sinx / (1-cosx)²
Maybe other people can check this result is correct.
2006-10-02 09:48:52 · answer #1 · answered by CHESSLARUS 7 · 0⤊ 0⤋
You had some mistake in the first derivative. Use the derivative division rule :
(f/g)´ = (f´g - fg´)/g^2 ( ...after simplifying we get )
y´= -1/(1-cosx) = 1/(cosx -1)
2006-10-02 09:47:53 · answer #2 · answered by vahucel 6 · 0⤊ 0⤋
answer: sin x / (cos x - 1)sqr
your calculator says the truth.
2006-10-02 09:49:22 · answer #3 · answered by Anonymous · 0⤊ 0⤋
d²/dx² = (sin(x) / ((cos(x) - 1)^2))
Don't you guys wish Yahoo Answers would let us enter mathematical expressions properly, instead of having to use parenthesis, and put everything on one line?
2006-10-02 09:53:37 · answer #4 · answered by عبد الله (ドラゴン) 5 · 0⤊ 0⤋