2x+18y+3z=36 Sketch the graph of the equation.?

Question

Label the points where graph crosses the x,y,z axis. I need to know how to find the points, and how i would plot them on a graph.

Answer 1

To find the intersection points:
1) First, set y and z equal to zero. Solve for x. You'll have point (x, 0, 0).

2) Second, set x and z equal to zero. Solve for y. You'll have point (0, y, 0).

3) Third, set x and y equal to zero. Solve for z. You'll have point (0, 0, z).

Repeat steps 1, 2, and 3. Substitute 1 instead of 0...then repeat and substitute 2...then...you get the picture. You should also get some negative values in the picture as well so you can get a better graph of the plane or shape.

Answer 2

This is the equation of a plane in space. To find where this plane crosses the axis you need to set two coordinates equal to zero and find the third, i.e.:

2*0+18*0+3*z=36 => z=12
2*0+18*y+3*0=36 => y=2
2*x+18*0+3*0=36 => x=18

Which means that the plane goes through the following points: (18,0,0), (0,2,0), and (0,0,12).

I hope this helps.

Answer 3

it quite is not an equation as no Y fee is indicated. definitely the cost of x or for this reason 2x is often constructive . as a result x= +2 or -2 definitely the of 2x it is +4 or -4 will become +4