2006-10-02 07:56:15 · 4 answers · asked by nicole s 1 in Science & Mathematics ➔ Mathematics
3(1-t)^2-2(1-t)+1
2006-10-02 07:58:05 · answer #1 · answered by thierryinho 2 · 0⤊ 0⤋
Substitute 1-t for x
g(1-t)=3(1-t)^2 - 2(1-t) +1
= 3(1-2t+t^2) -2(1-t) +1 square 1-t
=3-6t+3t^2 -2+2t +1 remove parentheses
= 3t^2 -4t +2 combine like terms
this cannot be factored so you'll have to use the quadratic formula or complete the square.
In either case, the answer is an imaginary number.
Are you supposed to go this far?
2006-10-02 16:08:50 · answer #2 · answered by mom 7 · 0⤊ 0⤋
Substitute 1-t for x. You get
g(1-t)=3(1-t)^2 - 2(1-t) + 1
= 3(1-2t+t^2) - 2 + 2t + 1
= 3 - 6t + 3t^2 + 2t - 1
= 3t^2 - 4t + 2
2006-10-02 14:58:36 · answer #3 · answered by James L 5 · 0⤊ 0⤋
g(1-t)=3(1-t)^2 - 2(1-t)+1
= 3(1-2t+t^2) - 2 + 2t + 1
= 3 - 6t + 3t^2 + 2t - 1
= 3t^2 - 4t + 2
2006-10-02 15:57:20 · answer #4 · answered by locuaz 7 · 0⤊ 0⤋