2006-10-02 07:44:57 · 3 answers · asked by nicole s 1 in Science & Mathematics ➔ Mathematics
center (-2,3)
y axis =tangent, so the radious is 2
(x+2)^2 + (y-3)^2=4
2006-10-02 08:59:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
To be tangent to the y-axis, the point (0,3) would be on the circle, so the radius would be 2. The reason for this is that the circle consists of all points of a given distance from the center, and since (-2,3) is 2 units away from the y-axis and the circle is tangent to the y-axis at the one point, it follows the circle consists of all points that are 2 units from the center.
Therefore, the equation is
(x+2)^2 + (y-3)^2 = 4.
2006-10-02 14:51:18 · answer #2 · answered by James L 5 · 0⤊ 0⤋
The equation of the circle having center at (-2,3) and touching y-axis will have radius=-2 =Equal to x coordinates of the cent re
(x+2)^2 + (y-3)^2 =2^2
x^2 +y^2+4x-6y=4-4-9=-9
x^2 +y^2+4x-6y+9=0
2006-10-02 14:55:00 · answer #3 · answered by Amar Soni 7 · 0⤊ 0⤋