H.W. Help: A single constant force of 23.3 N acts on a 3.6 kg particle of mass?

Question

The particle starts at rest at t = 0. What is the instantaneous power delivered by the force at
t = 4.13 s? Answer in W.

Answer 1

power =force*velocity
acceleration =force/mass=23.3/3.6
velocity at the end of 4.13 sec=v=u+at
=at because u=0
=23.3*4.13/3.6
Power=23.3*(23.3/3.6)*4.13=newtons*met/sec^2*sec
=newton-meter/sec=Joule/sec=watt
=622.815W

Answer 2

F = ma avg V = (39 meters) / (40 4 seconds) = 0.89 m / s very last V = avg V * 2 = 0.89 (meters / second) * 2 = a million.seventy 8 m / s a = replace in V / replace in T a = (a million.seventy 8 (m / s)) / (40 4 s) = 0.04 m / s2 86 N = m * 0.04 m / s2 m = 0.04 m / s2 / 86 N = 0.04 / 86 = 0.00046 kg