If there are 100 plain M&Ms, 27 peanut M&Ms and 173 Almond M&Ms in a container, what is the percent of the container by M&M?
2006-10-02 05:53:01 · 10 answers · asked by Sid 4 in Education & Reference ➔ Homework Help
That's easy...Let me do some math...
33.333%
2006-10-02 05:56:23 · answer #1 · answered by marisol 2 · 0⤊ 1⤋
That percentage has nothing to do with the actual M & Ms. For all we know, you may get an unrelated container & place the M &Ms in there.
2006-10-02 13:03:23 · answer #2 · answered by ? 6 · 0⤊ 0⤋
Well, there are 300 total M&M's in the container. So the percentage of each type is the number of them divided by 300. You do the rest.
2006-10-02 12:59:50 · answer #3 · answered by jurydoc 7 · 1⤊ 0⤋
300 total of which 100 are plain. To determine the percentage we divide 100 by 300 which comes out to .3333333..... or roughly 33 percent.
2006-10-02 12:58:44 · answer #4 · answered by ligoneskiing 4 · 0⤊ 1⤋
What is the percent of the container by M&M? Well i think you might be asking the percent of plain M&M's which would be 33.333333333333333333333333333%
2006-10-02 12:56:14 · answer #5 · answered by Sarah 2 · 1⤊ 0⤋
100% M&Msâ¢
2006-10-02 12:55:11 · answer #6 · answered by Dialup, Avatar, Jones!™ 2 · 1⤊ 0⤋
What, specifically, is the question? This is just the homework problem, what is YOUR question about it?
2006-10-02 12:55:51 · answer #7 · answered by Anonymous · 0⤊ 0⤋
sid i think something is missing..... you have told us how many of each type there are, but the question seems to be missing something.
2006-10-02 12:56:29 · answer #8 · answered by who be boo? 5 · 0⤊ 1⤋
33.333%
2006-10-02 16:27:42 · answer #9 · answered by modeledge 3 · 0⤊ 0⤋
100%.....
~PEACE~
2006-10-02 13:07:41 · answer #10 · answered by no_doubt! 5 · 0⤊ 0⤋