Is 250k Ohms that much different from 1.2m Ohms?

Question

I work with paint application, and having issues with prep coat (adhesion promoter). One product reads 250k and the other reads 1.2m. Is there a big difference between the readings?? By looking it up online, it appears that the difference is huge the lower you go. For instance, the difference between 15mOhm and 4mOhm is not as big a difference as 4mOhm to 250kOhm. Also, does this make a difference on the distance the current will have to travel?? Is 250k better than 4m to go a distance of 24"? Does the lower # act as a better gage wire for instance?

Answer 1

Yes, the lower numbers act as larger guage 'wires'.

As far as making a difference on how far the current has to travel, how much current are you talking about?

From the sounds of it, you need to get real familiar with Ohms Law ☺


Doug

Answer 2

First, you have to understand what these products are. Second, you should understand how they read. Third, you should understand how they work.

Just quickly, these products are resistors. They are measured in a unit called Ohms.

1000 Ohms=1Kilo Ohm(k ohm)
1000K Ohms=1Mega ohm(M ohm)
1 Mega Ohm= 1,000,000 Ohms

therefore, 250k Ohms=250 kilo Ohms=250,000 Ohms, and 1.2M Ohms=1.2 Mega Ohms=1,200,000 Ohms

note: 1.2M Ohms is greater than 250K Ohms by(1,200,000-250,000)950,000 Ohms or 950K Ohms.

15M Ohms=15,000,000 Ohms and 4M Ohms=4,000,000 Ohms, the difference is (15-4)11M Ohms or 11,000,000 Ohms.

the defference between 4M and 250K is 4,000,000-250,000=3,750,000.

Now, your reasoning about the defference should be vise versa.

About current, a resistor limits the amount of current passing through it. The higher the resistance the less the current through it and vise versa.

This brings us to Ohm's Law.http://www.grc.nasa.gov/WWW/K-12/Sample_Projects/Ohms_Law/ohmslaw.html

assume a constant voltage of 10volts and a resistance of a lower value,1 Ohm. The current that will pass through this resistance will be

I=V/R
I=10/1
I=10A(amperes)

Lower resistance(1 Ohm), high current flow (10A)

Now use another resistor of higher value, 100 Ohms ;
I=V/R
I=10/100
I=0.1A

Higher resistance(100 Ohms),lower current flow(0.1A)

Answer 3

There is confusion since you are not using same notation Thus:
A]1.2*10^6
.25*10^6 diff=.95*19^6
B]15*10^6
4* 10^6 diff=11*10^6
C] 4*10^6
.25*10^6 diff=3.75*10^6
you are mistaken in your statement about differences.
please see it carefully now that they are written in the same notation.I am sorry I will not be able to comment on which pair is better since I am not familiar with the physics involved.

Answer 4

It's almost 5 times the resistance, but what that means in your application is despendent upon power and desired output.

Answer 5

yes..