lim x->7 (x³ - 343)/(x² + 7x + 49)
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easy...
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2006-10-02 01:58:57 · 5 answers · asked by kevin! 5 in Science & Mathematics ➔ Mathematics
it is easy it is (x^3-7^3)/(x^2+7x+7^2)
the value is x-7 by divsion and putting x= 7 we get 0
Alternatively as denominator is not zero put the value and we get 0
2006-10-02 02:07:25 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
x² + 7x + 49 when x=7 is:
7² + 7(7) + 49 not cero, so to find the limit just write 7 instead of x:
lim x->7 (x³ - 343)/(x² + 7x + 49)
= (7³ - 343)/(7² + 7(7) + 49)=0
2006-10-02 11:21:36 · answer #2 · answered by locuaz 7 · 0⤊ 0⤋
1
2006-10-02 09:01:20 · answer #3 · answered by Tony M 7 · 0⤊ 1⤋
lim x^3-343
x-7 _______
x^2+7x+49
=7^3-343
_______
7^2+7(7)+49
= 343-343
_______
49+49+49
=0
___
147
=0
2006-10-05 04:24:41 · answer #4 · answered by srirad 2 · 0⤊ 0⤋
answer: 0
for x=7
0*147=0
2006-10-02 09:02:45 · answer #5 · answered by iyiogrenci 6 · 0⤊ 1⤋