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2006-10-02 00:05:31 · 1 answers · asked by Haskandi kalaza Josue 1 in Science & Mathematics Chemistry

1 answers

There are just too many for C3H6O2.

C2H4O2 is easier: There's acetic acid, methyl formate, 1,2-dioxacyclobutane, 1,3-dioxacyclobutane, methyldioxacyclopropane, R- and S-oxacyclopropanol, Z- and E-1,2-ethenediol, 1,1-ethenediol, and hydroxyacetaldehyde. Those are the only 11 ways I can think of to stick that combination of atoms together.

2006-10-02 04:26:04 · answer #1 · answered by Mr. E 5 · 1 0

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