2006-10-01 21:58:43 · 19 answers · asked by STEVEN G 1 in Education & Reference ➔ Homework Help
six sides
2006-10-01 22:01:18 · answer #1 · answered by S A 3 · 11⤊ 4⤋
Hexagon Sides
2016-12-11 10:22:29 · answer #2 · answered by ? 4 · 0⤊ 0⤋
6 sides dear
3 = triangle
4 = quadilateral
5 = pentagon
6 = hexagon
2006-10-01 23:04:51 · answer #3 · answered by chugh_aakriti 2 · 11⤊ 1⤋
6
2006-10-01 22:05:54 · answer #4 · answered by Anonymous · 6⤊ 3⤋
For the best answers, search on this site https://shorturl.im/8g1Rz
Before addressing the problem, consider a regular pentagon with unit sides. Draw a diagonal d and observe that d = 2*cos(36) from one side and d = 2*cos(72) + 1 from the other so that ½ = cos(36) - cos(72) = cos(36) - (2cos²(36)-1). Thus, cos²(36) = ½ (cos(36) + ½) = ½ (cos(36) + cos(60)) = cos(48) cos(12) = cos(48) * 2 * cos(60) * cos(12) = cos(48) * (cos(48) + cos(72)) or (A): cos²(36) - cos²(48) = cos(48) cos(72) Now, we are ready to address the original problem, and assume each side length is 1. Since ΔABC and ΔCDE are isosceles, AC = 2cos(48) and EC = 2cos(36). Now apply the law of cosines to FC of ΔAFC and ΔEFC: FC = 1 + 4cos²(48) - 4cos(48)cos(108) = 1 + 4cos²(36) - 4cos(36)cos(E-36) => cos²(48) + cos(48) cos(72) - cos²(36) + cos(36) * cos(E-36) = 0 => [by (A)] cos(36) * cos(E-36) = 0 => E-36 = 90 or E = 126 QED
2016-03-23 02:24:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋
6
2006-10-02 10:44:02 · answer #6 · answered by dalejrgurl008 2 · 7⤊ 4⤋
6 sides
5 for a pentagon
8 for an octagon
10 for a decagon
2006-10-01 22:00:57 · answer #7 · answered by zuj 3 · 10⤊ 1⤋
it has 6 sides
2015-04-30 09:48:47 · answer #8 · answered by jane 1 · 1⤊ 0⤋
How many sides are there on 12 hexagins
2015-10-08 17:01:48 · answer #9 · answered by NIK NIK MAC 1 · 2⤊ 0⤋
5
2006-10-01 22:00:19 · answer #10 · answered by Anonymous · 2⤊ 9⤋
7 sides
2014-03-05 10:28:22 · answer #11 · answered by Rosa 1 · 3⤊ 5⤋