p^2-6(p+1)-(8-p)
2006-10-01 20:23:04 · 5 answers · asked by andrew_at241 2 in Science & Mathematics ➔ Mathematics
firist put like terms together
p^-6(p+1)-(8-p)
= p^2-6p -6 -8 +p
= p^2-5p -14
now split -5 into two number s so that product is -14 2 and -7
= p^2+2p-7p-14
= p(p+2) -7(p+2) --------taking common factor
= (p+2)(p-7)
2006-10-01 20:40:02 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
P^2-6(P+1)-(8-P)
=p^2-6p-6-8+p
=p^2-5p-14
=p^2-7p+2p-14
=p(p-7)+2(p-7)
=(p-7)(p+2)
2006-10-02 04:50:18 · answer #2 · answered by sumi 1 · 0⤊ 0⤋
P^2-6P-6-8+P
=P^2-5P-14
=(P+2)(P-7)
2006-10-02 03:35:37 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
p² - 6(p + 1) - (8 -p)
p² - 6p - 6 - 8 + p
The distributive property and removing parenthesis
p² - 5p - 14
Collecting like terms
ask what factors when multiplied equals 14 and adding or subtracting equals 5.
2 Times 7 equal to 14 and 7 minus 2 equals 5
(P + 2)(p - 7)
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FOIL Method
(p + 2)(p - 7) = p² + 2x - 7x - 14= p² - 5p - 14
2006-10-02 07:37:58 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
yup that's right...
2006-10-02 03:40:04 · answer #5 · answered by O_w_A 2 · 0⤊ 0⤋