HOW do i calculate the angle or degree of triangle with 2 lines(5 metre each)and 1 line which is 8 metres.?

Answer 1

If we let a triangle ABC with angles A,B and C, and with opp. sides a,b, and c respectively, and let
a = b = 5 m and c = 8 m

Now, from the cosine rule,
c² = a² + b² - 2ab cos C,

solving for C,
C = arccos [(a² + b² - c²)/2ab]

We substitute values
C = arccos [-7/25]
C = 106 degrees 15 minutes 36.7369 seconds

^_^

Answer 2

that triangle is a right angled triangle so the angle opposite the hypotenuse(the 8 metre line one) has to be 90 degrees. Since all the angles in a triangle add up to 180, then the other two angles have to add up to 90. So each of the other angles are 45.

Answer 3

It is a question of proportion.
Each metre of line represents a degree of angle in the triangle.
The internal angles of a triangle total 180 degrees.
Total length (perimeter) = 18 m.
Ist angle: 5/18 x 180 = 50 degrees.
2nd angle: 5/18 x 180 = 50 degrees.
3rd angle: 8/18 x 180 =80 degrees.
This is an isosceles triangle- 2 equal sides = 2 equal angles.

Answer 4

From your Discription of the two sides is 5 Meters and the base is 8 meters

This is a isoscelis triangle

on your caculator

Use the Tan-¹

Since two sides are known

The tangent function is uses

5/5 = 1

Select 1 arc Tan-1 equals 45°

Answer 5

Two equal sides give you an isosceles triangle. The altitude of an isosceles triangle bisects the base of the triangle.The vertex angle will be defined by 2arcsin(4/5), and the two equal angles by (180-2arcsin(4/5))/2.

Answer 6

on account that there's a hypotenuse, you recognize that's a perfect triangle. in case you recognize that, you recognize the third perspective. you have right here a seventy 4.40 9 - ninety - 15.fifty one triangle. you recognize that the perspective opposite the seventy 4.40 9 deg perspective is two.9 meters. you do no longer quite desire this data, yet we are able to apply the regulation of sines: (sin74.40 9)/2.9 = (sin90)/x resolve for x

Answer 7

Drop a bisector from the apex of the two 5m lines to the 8m base. Now you have two symmetric right triangles, so you can use trig.