Newtons Laws involving tension, max mass, and few odds and ends...?

Question

http://img.photobucket.com/albums/v638/ravenatic20/cablecars.jpg
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The image shows a section of an alpine cable-car system. The maximum permissible mass of each car with occupants is 2800 kg. The cars, riding on a support cable, are pulled by a second cable attached to each pylon (support tower); assume the cables are straight. What is the difference in tension between adjacent sections of pull cable if the cars are at the maximum permissible mass and are being accelerated up the 35 degree incline at 0.81 m/s^2 ? Could you explain?

Answer 1

If the cables are straight the tension in them is infinite, and they snap, disastrously. However, for the purpose of this problem:
The difference in tension between adjacent sections of the pull cable is:
Fg = 2800*9.8sin35 per car, and the total tension on the cable is 0, theoretically
Fc =2800n*(0.81 + 9.8sin35) , n=count of cars from the bottom.
Each car requires the same force to accelerate. The forces are additive as you go up the system.

Answer 2

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