Physics 111 problem....just need a step in the right direction!!!?

Question

A grasshopper jumps 1.40 m from rest, with an initial velocity at a 47.0° angle with respect to the horizontal.
(a) Find the initial speed of the grasshopper.
m/s
(b) Find the maximum height reached.
m

i dont want the answer obviously, just a step in the right direction! because my friend has NO IDEA how to do it (and either do i because i havent taken physics yet lol)

Thank u!!!!

Answer 1

Call initial velocity v. Vertical component of v=v sin 47, horizontal component= v cos 47. v^2=2gs where g = gravitational acceleration and s= max height reached. The grasshopper will be in the air for time 2t (time taken on the way up=t and it takes an equal time on the way down) where s=(1/2)gt^2. During this time the grasshopper has been moving forward at a speed of v cos 47 so tv cos 47=1.4 metres.

Answer 2

Try drawing a diagram to portray the scenario. It might help.