A tennis ball with a speed of +11.3 m/s is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 8.99 m/s. If the ball is in contact with the wall for 0.0124 s, what is the average acceleration of the ball while it is in contact with the wall?
2006-10-01 15:56:52 · 4 answers · asked by warning9 2 in Science & Mathematics ➔ Physics
The ball's speed changes from 11.3 forward to 8.99 m/s backward, so the change is 11.3 + 8.99.
This change in velocity occurs over .0124 sec, so the average acceleration is (11.3 + 8.99) m/sec / .0124 sec = ____ m/sec^2
2006-10-01 17:24:26 · answer #1 · answered by actuator 5 · 0⤊ 0⤋
I failed Chen's Physics test
17.8/30
2006-10-01 23:04:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
it has no acceleration ?
2006-10-01 23:04:41 · answer #3 · answered by bob 3 · 0⤊ 0⤋
(11.3-8.99)??
2006-10-01 23:10:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋