physics help please?

Question

Ok, I realize this a very easy question but for some reason I'm just not getting the right answer. Please help me get this question. I'm not here for answers...Any help from you guys is greatly appreciated

A ball is thrown vertically upward from a window at 10 metres/second. It hits the ground 5 seconds later. What is the height of the window from the ground?

Anti can you please keep going with the explanation...if it's not too much to ask

Answer 1

Ok, whenever you have a pillar, or a cliff or a platform that is elevated and is not on the ground, and then you throw something vertically upward and allow it to fall till the GROUND, (i.e. not till the point of elevation); this is the formula: h = -ut + 1/2g t^2 (This is one of the basic formulas i've been taught at school).

h = -(10)5 + 1/2 (10) (5)(5)
= -50 + (5)(5)(5)
= -50 + 125
= 75 m

Answer 2

Consider the motion to consist of two pieces. The trip up to a halt, and the trip from apex (top) down to the ground.

First part is given by:

Vf = Vi - gTu

where Vf = 0 at the top, Vi = 10 m/s, g = 9.8 m/s^2, Tu is the time on the upward trip.

Solve for Tu

Td = T - Tu

where Td is the time downward from the apex

Use

Yi = VoTd - 1/2 g(Td)^2

where Yi is the initial height at the top, and Vo is the initial velocity which was 0.

Solved for Yi

Now go back to the toss up and calculate how far upward the ball went from the window

Y = Vi Tu and subtract that value of Y from the total height Yi to see how high the window is.

Aloha

Answer 3

Let 's' be the height reached when the ball is thrown vertically upward from the window.
then, 0=(10^2)-2gs
s=100/(2g)=50/g
let t be the time taken to reach the height s
then, 0=10-gt
t=10/g

If the ball hits the ground after 5 seconds. Time taken by the ball in falling =5-t=5-(10/g)

s' be the total height covered by the ball in falling
s'=1/2 g [{5-(10/g)}^2]
={(5g-10)^2} / {2g}

Therefore, height of the window from the ground (h) =s'-s
={(5g-10)^2} / {2g} - 50/g
_____________________________________

When we put g=9.8m/(s^2)
we get h = 72.5 metre
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When we put g=10m/(s^2)
we get h=75 metre

Answer 4

I'm rounding off here. In the first second it will reach the top of it's arc, and be at zero m/s (9.8 rounded to 10). This should be about 5 meters above the window. It will then fall for 4 seconds to the ground.
Can you figure out the height from there?

Answer 5

ok the formula for this is

V^2 - V0^2 = 2ax

ok so the velocity is up( so its positive) at 10 m/s

10^2 = 2(-9.8)x ( lets asume that 9.8 is 10, i dont have a calculator right now)

100 = 10x

so the height must be approx. 10 m up!

Answer 6

x(t) = 0.5a*t^2 + v0*t + x0.

you know a = g = -9.8 m/s^2
You are given v0 = 10m/s and x = 0 at time 5.

Plug in the numbers and you'll get your answer.